Offline Classroom Activities — Mathematics 6
Term 1 · Week 7 · Multiplying Any Combination · CG Quarter 1, competency 11
Five activities: three individual, two group. Every one of them runs with no electricity, no devices and no printing budget.
| Activity | Time | Grouping | Best used | |
|---|---|---|---|---|
| I-1 | The Four-Piece Rectangle | 25 min | Individual | Day 1 — replaces the digital game |
| I-2 | Conversion Sprint | 15 min | Individual | Day 2 — fluency, run twice |
| I-3 | The Whole-Number Hunt | 25 min | Individual | Day 4 — extension |
| G-1 | The Rectangle Wall | 35 min | Groups of 5 | Day 3 — consolidation |
| G-2 | Costing the Tarpaulin | 40 min | Teams of 5–6 | Day 5 — application |
Preparing the squared paper (once, reused all week)
Grade 6 needs squares more than Grade 5 did, because the four-piece rectangle is only convincing when the pieces can be counted. If you have no squared paper:
- Rule a 10 × 10 grid on one sheet in dark pen, then use it as a master — laid under a plain sheet against a window it shows through well enough to trace, and a class set can be ruled by five learners in one break.
- Or rule directly on the board and have learners copy only the rectangle they need.
- Or use the back of any grid-printed material — old score sheets, ledger paper, graph paper from a discarded exercise book.
About 4 gridded sheets per learner covers the week.
INDIVIDUAL ACTIVITIES
I-1 · The Four-Piece Rectangle
Time 25 minutes · Grouping Individual · Use Day 1, replaces the digital game
The learner draws the thing that makes the misconception impossible to hold.
Materials
- Squared paper, 1 sheet per learner
- Pencil and a ruler (or any straight edge)
Preparation
None. Write the five problems on the board.
Instructions
For each problem: draw the rectangle, cut it into four, label every piece, total them. Then check by converting to improper fractions.
| Problem | The four pieces | Total | Check by improper | |
|---|---|---|---|---|
| 1 | 2½ × 1⅓ | 2 · ½ · ⅔ · ⅙ | 3⅓ | 5/2 × 4/3 = 20/6 |
| 2 | 1½ × 2¼ | 2 · 1 · ¼ · ⅛ | 3⅜ | 3/2 × 9/4 = 27/8 |
| 3 | 2⅓ × 1½ | 2 · 1 · ⅓ · ⅙ | 3½ | 7/3 × 3/2 = 21/6 |
| 4 | 1¼ × 1⅘ | 1 · ⅘ · ¼ · ⅕ | 2¼ | 5/4 × 9/5 = 45/20 |
| 5 | 3½ × 1½ | 3 · 1½ · ½ · ¼ | 5¼ | 7/2 × 3/2 = 21/4 |
(Teacher's copy. Learners get column 2 only.)
Row 5 is the awkward one and it is deliberate. Its four pieces are 3 × 1 = 3, 3 × ½ = 1½, ½ × 1 = ½ and ½ × ½ = ¼. The second piece is itself a mixed number, which learners find unsettling — a piece of the answer looking like the question. It is correct, and saying so is the moment the method stops feeling like a trick.
The question to ask while circulating
"Point at the piece you would have missed on Monday."
A learner who cannot point at it has drawn the picture without connecting it to the error. That is the Day 2 small group.
Differentiation
| Group | Adjustment |
|---|---|
| Below level | Rows 1–3, halves and quarters. Pre-drawn rectangles so only the cutting and labelling is required |
| On level | All five |
| Above level | All five, then: "Draw 2⅓ × 2⅕. How many pieces? Why still four, and never more?" |
| Additional needs | Enlarged grids; pieces pre-outlined; labels may be dictated to a peer scribe |
Assessment — 10 points
| Criterion | Points |
|---|---|
| Five rectangles drawn and cut into four | 2 |
| All four pieces labelled correctly on at least three rows | 3 |
| Totals correct (1 point each, 5 rows) | 3 |
| Improper-fraction check shown and agreeing | 2 |
Written Works.
I-2 · Conversion Sprint
Time 15 minutes · Grouping Individual · Use Day 2 — and again on Day 4
Conversion is not the competency, but every failure of the competency this week traces back to it. Fifteen minutes of pure fluency, run twice in the week, buys more than an hour of product practice.
Materials
- Paper and pencil. Nothing else.
Instructions
Part A — mixed to improper. Two minutes. Then swap and mark.
| 2½ = 5/2 | 3¾ = 15/4 | 1⅚ = 11/6 | 4⅔ = 14/3 | 2⅗ = 13/5 |
| 5½ = 11/2 | 1⅞ = 15/8 | 3⅓ = 10/3 | 2¼ = 9/4 | 6⅖ = 32/5 |
Part B — improper to mixed. Two minutes.
| 7/2 = 3½ | 13/4 = 3¼ | 20/6 = 3⅓ | 11/3 = 3⅔ | 27/8 = 3⅜ |
| 9/5 = 1⅘ | 22/7 = 3 1/7 | 15/2 = 7½ | 45/20 = 2¼ | 52/5 = 10⅖ |
Part C — the trap. One minute, and it is worth the whole activity:
Which of these is not equal to the others? 2½ · 5/2 · 2.5 · 2/5 · 250%
Answer: 2/5. Everything else is the same quantity in different clothes — which is Quarter 2's whole subject arriving eight weeks early.
(Teacher's copy throughout. Learners get the left of each equals sign.)
How to run it
Time it strictly, swap papers, mark from the board, and record only the class total, not individual scores. This is a warm-up, not a test, and learners who know it is not being recorded will work faster and reveal more.
Run it again on Day 4 and compare the class total. That comparison is the evidence.
Differentiation
| Group | Adjustment |
|---|---|
| Below level | Part A only, first row only, untimed |
| On level | Parts A and B timed, Part C together |
| Above level | Add: "Write 20/6 in three different ways that are all correct." (20/6, 10/3, 3⅓) |
| Additional needs | Untimed; verbal answers accepted |
Assessment
Not scored individually. Record the class total on Day 2 and Day 4.
I-3 · The Whole-Number Hunt
Time 25 minutes · Grouping Individual · Use Day 4, extension
Runs the topic backwards. The answer is given; find the question. This is where a learner stops executing the rule and starts seeing inside it.
Materials
- Paper and pencil.
Instructions
Both numbers must be mixed numbers (a whole part and a fraction part). Find pairs whose product is exactly a whole number. Show the improper form that proves it.
| Target | Find at least |
|---|---|
| 3 | 3 pairs |
| 4 | 3 pairs |
| 6 | 2 pairs |
Answer key
Not exhaustive — accept any pair of mixed numbers that multiplies correctly.
| Target | Valid pairs | Improper form | Check |
|---|---|---|---|
| 3 | 2¼ × 1⅓ | 9/4 × 4/3 | 36/12 = 3 |
| 1¼ × 2⅖ | 5/4 × 12/5 | 60/20 = 3 | |
| 1⅔ × 1⅘ | 5/3 × 9/5 | 45/15 = 3 | |
| 2⅔ × 1⅛ | 8/3 × 9/8 | 72/24 = 3 | |
| 4 | 2½ × 1⅗ | 5/2 × 8/5 | 40/10 = 4 |
| 1½ × 2⅔ | 3/2 × 8/3 | 24/6 = 4 | |
| 3⅓ × 1⅕ | 10/3 × 6/5 | 60/15 = 4 | |
| 2⅖ × 1⅔ | 12/5 × 5/3 | 60/15 = 4 | |
| 6 | 2½ × 2⅖ | 5/2 × 12/5 | 60/10 = 6 |
| 2¼ × 2⅔ | 9/4 × 8/3 | 72/12 = 6 | |
| 1½ × 4 | — | rejected: 4 is not a mixed number |
The strategy worth surfacing at the end
Ask how learners found their pairs. Two methods appear, and the second is the prize:
- Guess and check. Convert, multiply, see. Slow but honest.
- Build it from the cancelling. For the product to be whole, the denominators must both cancel. So pick the first fraction — say 9/4 — and then the second must contain a 4 on top and a factor of 9 on the bottom: 4/3 works, because 4 cancels the 4 and 3 goes into 9.
Method 2 is factor reasoning, and it is what Grade 6 Quarter 4's GCF work is for. A learner who finds it should explain it slowly to the class.
Assessment
Open task, three bands:
| Band | Evidence |
|---|---|
| Extending | Met every target, found the cancelling method, can explain it |
| Secure | Met every target by guess and check, all products verified |
| Developing | Met some targets; the improper conversions are correct where attempted |
GROUP / TEAM ACTIVITIES
Both assume a crowded room with fixed desks. Neither requires learners to move furniture.
G-1 · The Rectangle Wall
Time 35 minutes · Groups of 5 · Use Day 3, consolidation
Six groups, six rectangles, one wall display that stays up for the rest of the term.
Materials
- One large sheet per group — cartolina, newspaper, or taped-together bond paper
- Pencil, ruler, and something to shade with
- Tape or paste
Preparation
Write the assignments on the board before the class comes in.
| Group | Product | Answer |
|---|---|---|
| 1 | 1½ × 1½ | 2¼ |
| 2 | 2½ × 1½ | 3¾ |
| 3 | 1⅓ × 2¼ | 3 |
| 4 | 2⅓ × 1½ | 3½ |
| 5 | 1¾ × 2⅔ | 4⅔ |
| 6 | 2⅕ × 1½ | 3 3/10 |
Roles — assign one to each member, do not let them volunteer
| Role | Responsibility |
|---|---|
| Drafter | Draws the rectangle to scale and cuts it into four. Draws nothing else |
| Labeller | Writes the dimension of each side and the area of each of the four pieces |
| Adder | Totals the four pieces, showing the common denominator. May not use the improper method |
| Checker | Independently converts to improper fractions and multiplies. Signs the sheet |
| Reporter | Presents to the class and answers one question from another team |
The split between Adder and Checker is the whole design: the two methods must be performed by two different people, so that agreement is evidence rather than assumption.
Instructions
- 5 min — roles assigned, rectangle drawn to scale.
- 15 min — cut into four, label, total.
- 8 min — Checker converts and multiplies independently. If the two answers disagree, both people work again — the group may not simply take one.
- 7 min — sheets taped up in order, Reporters present.
Answer key — the four pieces
| Group | Product | Four pieces | Total | Improper check |
|---|---|---|---|---|
| 1 | 1½ × 1½ | 1 · ½ · ½ · ¼ | 2¼ | 3/2 × 3/2 = 9/4 |
| 2 | 2½ × 1½ | 2 · 1 · ½ · ¼ | 3¾ | 5/2 × 3/2 = 15/4 |
| 3 | 1⅓ × 2¼ | 2 · ¼ · ⅔ · 1/12 | 3 | 4/3 × 9/4 = 36/12 |
| 4 | 2⅓ × 1½ | 2 · 1 · ⅓ · ⅙ | 3½ | 7/3 × 3/2 = 21/6 |
| 5 | 1¾ × 2⅔ | 2 · ⅔ · 1½ · ½ | 4⅔ | 7/4 × 8/3 = 56/12 |
| 6 | 2⅕ × 1½ | 2 · 1 · ⅕ · 1/10 | 3 3/10 | 11/5 × 3/2 = 33/10 |
Group 3's answer is exactly 3, and Group 5's has a mixed number among its pieces. Both groups will suspect an error. Both are right. Have those two Reporters go last, so the class has settled before the surprises arrive.
Managing 45+ learners at fixed desks
Six groups of five leaves room for more — add 1⅖ × 2½ (= 3½) and 3¼ × 1⅓ (= 4⅓) as groups 7 and 8. Nobody moves; the group is whoever is within reach, and the sheet passes along the row.
Differentiation
| Group | Adjustment |
|---|---|
| Below level | Assign group 1 or 2 — halves only, smallest pieces |
| Above level | Assign group 5 or 6, and ask them to predict a seventh product without drawing it |
| Additional needs | The Adder and Checker roles are entirely written; the Drafter role can use a pre-ruled grid |
Assessment — group rubric, 12 points
| Criterion | 3 | 2 | 1 |
|---|---|---|---|
| Rectangle | To scale, cut correctly into four, legible from the back of the room | Correct but not to scale | Wrong number of pieces |
| Labelling | All four pieces and both dimensions labelled correctly | One label wrong or missing | Several missing |
| Two methods agree | Both performed independently and agree, with working shown for each | Agree, but one is thin | Only one method attempted |
| Roles | Every member did their own role only | Roles blurred once or twice | One or two members did everything |
Performance Tasks.
G-2 · Costing the Tarpaulin
Time 40 minutes · Teams of 5–6 · Use Day 5, application
The week's arithmetic inside a job that gets done in every barangay before every fiesta.
Materials
- Paper and pencil per team
- The price list below, copied onto the board
Preparation — 5 minutes
Write on the board:
TARPAULIN PRINTING — PRICE LIST
Printing ₱ 180 per square metre
Eyelets ₱ 12 each
Hemming ₱ 45 per metre of edge
Roles
| Role | Responsibility |
|---|---|
| Reader | Reads each requirement aloud and states what must be computed. May not compute |
| Measurer | Works out areas and edge lengths |
| Coster | Turns measurements into pesos |
| Checker | Recomputes every figure independently. Signs each line |
| Reporter | Presents and answers one question |
| Timekeeper (6th) | Calls the halfway point and the two-minute warning |
Instructions
Part 1 — 12 min. One banner. The barangay wants a tarpaulin 2½ m wide and 1½ m tall. Find its area, then the printing cost.
Part 2 — 14 min. The full job. The same banner needs hemming all the way round and an eyelet every half-metre of edge. Find the perimeter, the hemming cost, the number of eyelets, and the total.
Part 3 — 8 min. The decision. A second design is 3 m × 1¼ m. Which banner has the larger area? Which costs more in total? Are those the same answer? Explain.
Part 4 — 6 min. Reporters present Part 3. Take three teams.
Answer key
Part 1 — the banner
| Step | Working | Answer |
|---|---|---|
| Area | 5/2 × 3/2 = 15/4 | 3¾ sq m |
| Printing | 180 × 15/4 = 2700/4 | ₱675 |
Part 2 — the full job
| Step | Working | Answer |
|---|---|---|
| Perimeter | 2 × (2½ + 1½) = 2 × 4 | 8 m |
| Hemming | 45 × 8 | ₱360 |
| Eyelets | 8 ÷ ½ | 16 |
| Eyelet cost | 12 × 16 | ₱192 |
| Total | 675 + 360 + 192 | ₱1 227 |
Part 3 — the decision
| Banner A — 2½ × 1½ | Banner B — 3 × 1¼ | |
|---|---|---|
| Area | 15/4 = 3¾ sq m | 15/4 = 3¾ sq m |
| Printing | ₱675 | ₱675 |
| Perimeter | 2 × 4 = 8 m | 2 × 4¼ = 8½ m |
| Hemming | ₱360 | 45 × 17/2 = ₱382.50 |
| Eyelets | 8 ÷ ½ = 16 → ₱192 | 8½ ÷ ½ = 17 → ₱204 |
| Total | ₱1 227 | ₱1 261.50 |
The two banners have exactly the same area and different costs, and that is the entire point of Part 3. Same 3¾ sq m, same printing bill — but B is longer and thinner, so it has more edge, and edge is what hemming and eyelets are sold by. A team that answers "the bigger one costs more" has not read the question; the areas are identical.
Expect at least one team to insist the areas differ. Have them show their working — it is almost always 3 × 1¼ computed as 3¼.
Managing 45+ learners at fixed desks
Teams are rows. Only the Reader and Reporter stand. With more than eight teams, run Part 4 with four reporters and collect Part 3 in writing from the rest.
Differentiation
| Group | Adjustment |
|---|---|
| Below level | Parts 1 and 2 only, with the area calculation modelled on the board first |
| On level | Parts 1–3 |
| Above level | Add Part 3b — "Design a banner with the same 3¾ sq m area and the lowest possible total cost. Justify the shape." (A square-ish 2 m × 1⅞ m has the least perimeter of the practical options) |
| Language support | The Reader role may be performed in the mother tongue; the written record is in English |
| Additional needs | Coster may use a calculator; Reporter may present from written notes |
Assessment — group rubric, 12 points
| Criterion | 3 | 2 | 1 |
|---|---|---|---|
| Part 1 | Area and cost both correct, working shown | One correct | Neither |
| Part 2 | Perimeter, hemming, eyelets and total all correct | Two or three correct | One or none |
| Part 3 reasoning | Recognises the areas are equal and explains that cost differs because of edge, not area | Notices the totals differ, explanation thin | Claims the areas differ |
| Roles and verification | Every role performed; Checker signed each line | Roles blurred, checking partial | One or two members did everything |
Performance Tasks.
Which activity to reach for
| If your class… | Run |
|---|---|
| Has no devices at all | I-1 on Day 1 and I-2 on Days 2 and 4 — together they replace the game |
| Still produces part-by-part answers after Day 2 | I-1 again, rows 1–3, with pre-drawn rectangles |
| Is slow and inaccurate rather than confused | I-2. The problem is conversion fluency, not understanding |
| Finished early and is restless | I-3. It has no ceiling |
| Needs the term performance-task mark | G-1 or G-2 — both rubric-scored and defensible as Performance Tasks |
| Has one 40-minute slot and nothing prepared | G-2. The only preparation is three lines on the board |
Part of the E-turo MATATAG artifact set. Companion files:
lesson-plan.md · lesson-plan-ilaw.md ·
syllabus.md · assessment.md ·
slides.html · game.html ·
worksheet.html